Ядро Entity Framework не работает с проверкой подлинности Windows

#entity-framework #entity-framework-core

#entity-framework #entity-framework-core

Вопрос:

Всякий раз, когда я пытаюсь подключиться к базе данных, я получаю это исключение

 Unhandled Exception: System.Data.SqlClient.SqlException: Cannot open database "TrackTvDb" requested by the login. The login failed.
Login failed for user 'DESKTOP-MTHC289hristo.kolev'.
   at System.Data.SqlClient.SqlInternalConnectionTds..ctor(DbConnectionPoolIdentity identity, SqlConnectionString connectionOptions, Object providerInfo, Boolean redirectedUserInstance, SqlConnectionString userConnectionOptions, SessionData reconnectSessionData, Boolean applyTransientFaultHandling)
   at System.Data.SqlClient.SqlConnectionFactory.CreateConnection(DbConnectionOptions options, DbConnectionPoolKey poolKey, Object poolGroupProviderInfo, DbConnectionPool pool, DbConnection owningConnection, DbConnectionOptions userOptions)
   at System.Data.ProviderBase.DbConnectionFactory.CreatePooledConnection(DbConnectionPool pool, DbConnection owningObject, DbConnectionOptions options, DbConnectionPoolKey poolKey, DbConnectionOptions userOptions)
   at System.Data.ProviderBase.DbConnectionPool.CreateObject(DbConnection owningObject, DbConnectionOptions userOptions, DbConnectionInternal oldConnection)
   at System.Data.ProviderBase.DbConnectionPool.UserCreateRequest(DbConnection owningObject, DbConnectionOptions userOptions, DbConnectionInternal oldConnection)
   at System.Data.ProviderBase.DbConnectionPool.TryGetConnection(DbConnection owningObject, UInt32 waitForMultipleObjectsTimeout, Boolean allowCreate, Boolean onlyOneCheckConnection, DbConnectionOptions userOptions, DbConnectionInternalamp; connection)
   at System.Data.ProviderBase.DbConnectionPool.WaitForPendingOpen()
--- End of stack trace from previous location where exception was thrown ---
   at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)
   at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)
   at Microsoft.EntityFrameworkCore.Storage.RelationalConnection.<OpenAsync>d__31.MoveNext()
--- End of stack trace from previous location where exception was thrown ---
   at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)
   at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)
   at Microsoft.EntityFrameworkCore.Query.Internal.AsyncQueryingEnumerable.AsyncEnumerator.<MoveNext>d__8.MoveNext()
--- End of stack trace from previous location where exception was thrown ---
   at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)
   at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)
   at Microsoft.EntityFrameworkCore.Query.AsyncQueryMethodProvider.<GetResult>d__16`1.MoveNext()
--- End of stack trace from previous location where exception was thrown ---
   at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)
   at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)
   at Microsoft.EntityFrameworkCore.Query.Internal.TaskResultAsyncEnumerable`1.Enumerator.<MoveNext>d__3.MoveNext()
--- End of stack trace from previous location where exception was thrown ---
   at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)
   at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)
   at Microsoft.EntityFrameworkCore.Query.Internal.AsyncLinqOperatorProvider.ExceptionInterceptor`1.EnumeratorExceptionInterceptor.<MoveNext>d__5.MoveNext()
--- End of stack trace from previous location where exception was thrown ---
   at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)
   at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)
   at System.Runtime.CompilerServices.TaskAwaiter`1.GetResult()
   at ManualTesting.EntryPint.<MainAsync>d__1.MoveNext()
--- End of stack trace from previous location where exception was thrown ---
   at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)
   at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)
   at System.Runtime.CompilerServices.TaskAwaiter.GetResult()
   at ManualTesting.EntryPint.Main(String[] args)
  

У меня есть SQLServer 2016, и это приложение .Net Core.

Вот DbContext

 namespace TrackTv
{
    using Microsoft.EntityFrameworkCore;

    using TrackTv.Models;
    using TrackTv.Models.Joint;

    public class TrackTvDbContext : DbContext
    {
        public DbSet<Actor> Actors { get; set; }

        public DbSet<Episode> Episodes { get; set; }

        public DbSet<Genre> Genres { get; set; }

        public DbSet<Network> Networks { get; set; }

        public DbSet<Show> Shows { get; set; }

        public DbSet<User> Users { get; set; }

        protected override void OnConfiguring(DbContextOptionsBuilder builder)
        {
            builder.UseSqlServer(@"Server=.;Database=TrackTvDb;Trusted_Connection=True;MultipleActiveResultSets=True;");

            base.OnConfiguring(builder);
        }

        protected override void OnModelCreating(ModelBuilder modelBuilder)
        {
            // ShowsUsers
            modelBuilder.Entity<ShowsUsers>().HasKey(t => new
                        {
                            t.UserId,
                            t.ShowId
                        });
            modelBuilder.Entity<ShowsUsers>().HasOne(t => t.User).WithMany(user => user.ShowsUsers).HasForeignKey(t => t.UserId);
            modelBuilder.Entity<ShowsUsers>().HasOne(t => t.Show).WithMany(show => show.ShowsUsers).HasForeignKey(t => t.ShowId);

            // ShowsActors
            modelBuilder.Entity<ShowsActors>().HasKey(t => new
                        {
                            t.ShowId,
                            t.ActorId
                        });
            modelBuilder.Entity<ShowsActors>().HasOne(t => t.Show).WithMany(show => show.ShowsActors).HasForeignKey(t => t.ShowId);
            modelBuilder.Entity<ShowsActors>().HasOne(t => t.Actor).WithMany(actor => actor.ShowsActors).HasForeignKey(t => t.ActorId);

            // ShowsGenres
            modelBuilder.Entity<ShowsGenres>().HasKey(t => new
                        {
                            t.ShowId,
                            t.GenreId
                        });
            modelBuilder.Entity<ShowsGenres>().HasOne(t => t.Show).WithMany(show => show.ShowsGenres).HasForeignKey(t => t.ShowId);
            modelBuilder.Entity<ShowsGenres>().HasOne(t => t.Genre).WithMany(genre => genre.ShowsGenres).HasForeignKey(t => t.GenreId);
        }
    }
}
  

Мой project.json

 {
  "version": "1.0.0-*",
  "buildOptions": {
    "emitEntryPoint": true
  },

  "frameworks": {
    "netcoreapp1.0": {
      "dependencies": {
        "Microsoft.NETCore.App": {
          "type": "platform",
          "version": "1.0.1"
        },
        "TrackTv": "*",
        "Microsoft.EntityFrameworkCore.SqlServer": "1.0.1"
      }
    }
  }
}
  

Я могу войти в систему с помощью Management Studio следующим образом:

У меня есть несколько других рабочих.СЕТЕВЫЕ приложения, которые обращаются к этому экземпляру SQLServer с помощью EF6.

Ответ №1:

Не могли бы вы попробовать добавить встроенный атрибут безопасности в строку подключения?

  builder.UseSqlServer(@"Server=.;Database=TrackTvDb;Trusted_Connection=True;MultipleActiveResultSets=True;Integrated Security=true");
  

Комментарии:

1. Нет, Trusted_Connection=True делает то, что Integrated Security=true делает. Я пробовал это.