#sql #oracle #query-performance
#sql #Oracle #запрос-производительность
Вопрос:
Я пытаюсь извлечь только одну строку из восьми столбцов, используя встроенные представления.
Однако существует значительное совпадение. Я не очень хорошо использую PL / SQL.
Как я могу упростить код SQL и повысить производительность запросов?
Я создал индекс в столбце ‘CARD_NUM’ и столбце ‘CARD_TRANSACTION_TIME’.
Производительность значительно улучшилась, но с 10 миллионами данных все еще существует задержка.
Я был бы признателен за вашу помощь.
WITH WHOLE AS (SELECT CARD_TRANSACTION_TIME, CARD_TRANSACTION_AMOUNT, CARD_TRANSACTION_CONTENT, INDUSTRY_CODE
FROM CARD_TRANSACTION_TEST01
WHERE CARD_NUM IN(SELECT CARD_NUM FROM CARD_CONTRACT_TEST01 WHERE RESI_NUM = '9203101937988')
AND TO_CHAR(CARD_TRANSACTION_TIME, 'YYYY') = '2020'
AND TO_CHAR(CARD_TRANSACTION_TIME, 'MM') = '01'
UNION ALL
SELECT CARD_TRANSACTION_TIME, CARD_TRANSACTION_AMOUNT, CARD_TRANSACTION_CONTENT, INDUSTRY_CODE
FROM OPEN_CARD_TRANSACTION_TEST01
WHERE RESI_NUM = '9203101937988'
AND TO_CHAR(CARD_TRANSACTION_TIME, 'YYYY') = '2020'
AND TO_CHAR(CARD_TRANSACTION_TIME, 'MM') = '01'
AND MEANS IN('cardOne', 'cardTwo')
)
SELECT SUBQUERY1.RESULT AS TYPE1, SUBQUERY2.RESULT AS "TYPE2", SUBQUERY3.RESULT AS "TYPE3", SUBQUERY4.RESULT AS "TYPE4",
SUBQUERY5.RESULT AS "TYPE5", SUBQUERY6.RESULT AS "TYPE6", SUBQUERY7.RESULT AS "TYPE7", SUBQUERY8.RESULT AS "TYPE8"
FROM (SELECT *
FROM (SELECT SUM(RESULT) AS RESULT
FROM(
SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
FROM WHOLE
GROUP BY INDUSTRY_CODE
HAVING INDUSTRY_CODE IN('I1', 'I2')
UNION ALL
-- SELECT NULL AS NUM
SELECT 0 AS RESULT
FROM DUAL))
WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY1,
(SELECT *
FROM (SELECT SUM(RESULT) AS RESULT
FROM(
SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
FROM WHOLE
GROUP BY INDUSTRY_CODE
HAVING INDUSTRY_CODE IN('I4', 'I5', 'I6')
UNION ALL
-- SELECT NULL AS NUM
SELECT 0 AS RESULT
FROM DUAL))
WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY2,
(SELECT *
FROM (SELECT SUM(RESULT) AS RESULT
FROM(
SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
FROM WHOLE
GROUP BY INDUSTRY_CODE
HAVING INDUSTRY_CODE IN('I7', 'I8')
UNION ALL
-- SELECT NULL AS NUM
SELECT 0 AS RESULT
FROM DUAL))
WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY3,
(SELECT *
FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
FROM WHOLE
GROUP BY INDUSTRY_CODE
HAVING INDUSTRY_CODE IN('I9')
UNION ALL
-- SELECT NULL AS NUM
SELECT 0 AS RESULT
FROM DUAL)
WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY4,
(SELECT *
FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
FROM WHOLE
GROUP BY INDUSTRY_CODE
HAVING INDUSTRY_CODE IN('I10')
UNION ALL
-- SELECT NULL AS NUM
SELECT 0 AS RESULT
FROM DUAL)
WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY5,
(SELECT *
FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
FROM WHOLE
GROUP BY INDUSTRY_CODE
HAVING INDUSTRY_CODE IN('I11')
UNION ALL
-- SELECT NULL AS NUM
SELECT 0 AS RESULT
FROM DUAL)
WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY6,
(SELECT *
FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
FROM WHOLE
GROUP BY INDUSTRY_CODE
HAVING INDUSTRY_CODE IN('I12')
UNION ALL
-- SELECT NULL AS NUM
SELECT 0 AS RESULT
FROM DUAL)
WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY7,
(SELECT *
FROM (SELECT SUM(CARD_TRANSACTION_AMOUNT) AS RESULT
FROM WHOLE
GROUP BY INDUSTRY_CODE
HAVING INDUSTRY_CODE IN('I13')
UNION ALL
-- SELECT NULL AS NUM
SELECT 0 AS RESULT
FROM DUAL)
WHERE RESULT IS NOT NULL OR ROWNUM = 1) SUBQUERY8
WHERE ROWNUM <=1;
Ответ №1:
Я упростил запрос, поскольку у вас одинаковая группа по для всех подзапросов, мы можем просто использовать условную агрегацию вместо нескольких подзапросов.
Не могли бы вы проверить, поскольку я не могу проверить синтаксическую корректность запроса из-за объектов схемы.
with whole as
(
select card_transaction_time, card_transaction_amount, card_transaction_content, industry_code
from card_transaction_test01
where card_num in (select card_num from card_contract_test01 where resi_num = '9203101937988')
and extract(year from card_transaction_time) = 2020
and extract(month from card_transaction_time) = 1
union all
select card_transaction_time, card_transaction_amount, card_transaction_content, industry_code
from open_card_transaction_test01
where resi_num = '9203101937988'
and extract(year from card_transaction_time) = 2020
and extract(month from card_transaction_time) = 1
and means in('cardOne', 'cardTwo')
)
select result1 as TYPE1
, result2 as TYPE2
, result3 as TYPE3
, result4 as TYPE4
, result5 as TYPE5
, result6 as TYPE6
, result7 as TYPE7
, result8 as TYPE8
from
(
select sum(case when industry_code in ('I1', 'I2') then card_transaction_amount else 0 end) as result1
, sum(case when industry_code in ('I4', 'I5', 'I6') then card_transaction_amount else 0 end) as result2
, sum(case when industry_code in ('I7', 'I8') then card_transaction_amount else 0 end) as result3
, sum(case when industry_code in ('I9') then card_transaction_amount else 0 end) as result4
, sum(case when industry_code in ('I10') then card_transaction_amount else 0 end) as result5
, sum(case when industry_code in ('I11') then card_transaction_amount else 0 end) as result6
, sum(case when industry_code in ('I12') then card_transaction_amount else 0 end) as result7
, sum(case when industry_code in ('I13') then card_transaction_amount else 0 end) as result8
from whole
group by industry_code
);
Комментарии:
1. есть несколько строк. Я думаю, что могу это решить. большое вам спасибо!