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Я написал следующее на python, используя модуль mechanize, чтобы распечатать HTML из списка URL-адресов:

 import mechanize, fileinput

urls = open('F:Pythonurl_list.txt')
content = [x.strip() for x in urls.readlines()]
print content

browser = mechanize.Browser()
browser.open("https://login.asp")
browser.select_form(nr=0)
browser['desc'] = "xxxxx"
browser['password'] = "xxxxx"
response = browser.submit()
logincheck = response.read()

print logincheck

# now logged into site, loop through the list of urls read in from the text file and print the html for each one:

for s in content:

    releasenote = browser.urlopen(s) 
    # error here, should be releasenote = browser.open(s)

    print  releasenote.geturl()
    print  releasenote.info()
    print  releasenote.read()
  

Однако я просто получаю следующую ошибку в оболочке python:

 Traceback (most recent call last):
File "F:Pythontest.py", line 20, in <module>
releasenote = browser.urlopen(s)
File "C:Python27libsite-packagesmechanize_mechanize.py", line 628, in __getattr__
".select_form()?)" % (self.__class__, name))
AttributeError: mechanize._mechanize.Browser instance has no attribute urlopen (perhaps you forgot to .select_form()?)
  

Что я делаю не так? Приветствия!

Это mechanize.urlopen(s)

или как вы сказали browser.open(s) .