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У меня есть вопрос о домашнем задании с просьбой ввести 5 результатов тестов и вычислить эквивалентную буквенную оценку, а затем выполнить среднее значение и применить к нему также буквенную оценку.

В настоящее время у меня есть рабочая программа, но я хотел посмотреть, возможно ли получить все результаты, просто используя один набор операторов ‘if’

 def letter_grade(test1, test2, test3, test4, test5, average):
    if test1 >= 90 and test1 <=100:
        score1 = "A"
    elif test1 >= 80 and test1 <= 89:
        score1 = "B"
    elif test1 >= 70 and test1 <= 79:
        score1 = "C"
    elif test1 >= 60 and test1 <= 69:
        score1 = "D"
    elif test1 < 60:
        score1 = "F"


    if test2 >= 90 and test2 <=100:
        score2 = "A"
    elif test2 >= 80 and test2 <= 89:
        score2 = "B"
    elif test2 >= 70 and test2 <= 79:
        score2 = "C"
    elif test2 >= 60 and test2 <= 69:
        score2 = "D"
    elif test2 < 60:
        score2 = "F"


    if test3 >= 90 and test3 <=100:
        score3 = "A"
    elif test3 >= 80 and test3 <= 89:
        score3 = "B"
    elif test3 >= 70 and test3 <= 79:
        score3 = "C"
    elif test3 >= 60 and test3 <= 69:
        score3 = "D"
    elif test3 < 60:
        score3 = "F"


    if test4 >= 90 and test4 <=100:
        score4 = "A"
    elif test4 >= 80 and test4 <= 89:
        score4 = "B"
    elif test4 >= 70 and test4 <= 79:
        score4 = "C"
    elif test4 >= 60 and test4 <= 69:
        score4 = "D"
    elif test4 < 60:
        score4 = "F"



    if test5 >= 90 and test5 <=100:
        score5 = "A"
    elif test5 >= 80 and test5 <= 89:
        score5 = "B"
    elif test5 >= 70 and test5 <= 79:
        score5 = "C"
    elif test5 >= 60 and test5 <= 69:
        score5 = "D"
    elif test5 < 60:
        score5 = "F"


    if average >= 90 and average <=100:
        avgScore = "A"
    elif average >= 80 and average <= 89:
        avgScore = "B"
    elif average >= 70 and average <= 79:
        avgScore = "C"
    elif average >= 60 and average <= 69:
        avgScore = "D"
    elif average < 60:
        avgScore = "F"
    return score1, score2, score3, score4, score5, avgScore
  

Я бы хотел, чтобы функция возвращала оценки букв более эффективным способом, если это возможно.

Просто определите функцию, а затем используйте ее для оценки каждого теста и среднего значения:

 def letter_grade(score):
    if 90 <= score <= 100:
        grade = "A"
    elif 80 <= score <= 89:
        grade = "B"
    elif 70 <= score <= 79:
        grade = "C"
    elif 60 <= score <= 69:
        grade = "D"
    elif score < 60:
        grade = "F"
    return grade


tests = [50, 60, 65, 99, 25]

for test in tests:
    print(f"score: {test}, grade: {letter_grade(test)}")

print("average grade:", letter_grade(sum(tests) / len(tests)))
  

Вывод:

 score: 50, grade: F
score: 60, grade: D
score: 65, grade: D
score: 99, grade: A
score: 25, grade: F
average grade: F